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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -1,21 +1,46 @@ | ||
| # Authoring recursive algorithms. Add comments including time and space complexity for each method. | ||
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| # Time complexity: ? | ||
| # Space complexity: ? | ||
| # Time complexity: O(n), because of the size of the stack (number of methods that is accumulated in the stack to run) | ||
| # Space complexity: O(n), because of the size of this stack | ||
| def factorial(n) | ||
| raise NotImplementedError, "Method not implemented" | ||
| #Base Case | ||
| return 1 if n == 0 | ||
| raise ArgumentError if n < 0 | ||
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| #Recursive Case | ||
| return n * factorial(n-1) | ||
| end | ||
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| # Time complexity: ? | ||
| # Space complexity: ? | ||
| def reverse(s) | ||
| raise NotImplementedError, "Method not implemented" | ||
| # Time complexity: O(n), it will iterate through all elements of string | ||
| # Space complexity: O(1), it will always use same number of variables (i, j, memo) | ||
| def reverse(s ) | ||
| i = 0 | ||
| j = s.length - 1 | ||
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| while i < j | ||
| memo = s[i] | ||
| s[i] = s[j] | ||
| s[j] = memo | ||
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| i += 1 | ||
| j -= 1 | ||
| end | ||
|
Comment on lines
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. A |
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| return s | ||
| end | ||
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| # Time complexity: ? | ||
| # Space complexity: ? | ||
| def reverse_inplace(s) | ||
| raise NotImplementedError, "Method not implemented" | ||
| # Time complexity: O(n) ~ n/2 as increasing and decreasing both pointer in same call | ||
| # Space complexity: O(n), n/2 recursive calls, | ||
| # because both pointers are moving each time the method is called | ||
| def reverse_inplace(s, i = 0, j = s.length - 1) | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 Great work! |
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| #Base Case | ||
| return s if i >= j | ||
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| #Recursive Case | ||
| memo = s[i] | ||
| s[i] = s[j] | ||
| s[j] = memo | ||
| return reverse_inplace(s, i + 1, j - 1) | ||
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| end | ||
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| # Time complexity: ? | ||
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👍