Unable to login() after checkin()

[ghost]

In TestGooglePlayCrawler.java, login() will be failed by using the android-id generated after run checkin().
Listcommand also failed.

[HenryHoggard]

Duplicate of #28 , currently working on a fix.

[ghost]

I wonder why googleplay client still works, if the request is disabled.@HenryHoggard.

[filamoon]

@HenryHoggard Please kindly keep us posted :)

[Akdeniz]

I don't know why but google started to require a parameter named "client_sig" on authentication, which is kind of a identity for login service system apk. By the way its value does not matter, as far as tested. Weird!

Anyway, last commit should work.

[ghost]

@Akdeniz How you test it out? On your android device?

[Akdeniz]

@uptown1919 No, I prefer to use emulator.

[spacegom]

@Akdeniz Thanks alot!!!!!

[CodeheadUK]

@Akdeniz
Wow, quick fix! Great work, thank you.
Care to share how you pulled the API apart? I was poking around yesterday trying to work out where the problem was, but didn't get very far.

[HenryHoggard]

@CodeheadUK The way I did it was if you use a proxy to view the requests you will see that you get 404 or error 500 unless you add client_sig to the requests. I discovered it was client_sig by comparing the checkin request to the search request because checkin still worked and search didn't. After trial and error I found that client_sig was the difference between the two requests.

[CodeheadUK]

@HenryHoggard, Thanks for the info.
I saw the 404 and convinced myself that URL_LOGIN was wrong or had changed. I figured that I could snag the traffic from an emulator for more info, but got put off by the https encryption.

[filamoon]

@CodeheadUK Here is what I did with https on my device:

I'm using the Charles proxy tool that comes with a SSL certificate. Install the certificate to the phone. Then in wifi settings, enable advanced options and set the proxy IP and port accordingly. Enable SSL proxy in Charles, then you will be able to decrypt the https payload.

[CodeheadUK]

Top tips, Thanks @filamoon.

[qwertydzen]

@Akdeniz thank you for the fix