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Update README.md
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README.md

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### ➢ Now the model is **balanced**: [66 = 66]()
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#
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### [Feasible Solution Example]():
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🟡 The values in the matrix represent the **quantities transported**.
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🟠 $begin:math:text$ X_{A2} = 1 $end:math:text$, $begin:math:text$ X_{A3} = 5 $end:math:text$: These are **unsatisfied demands**.
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## 🧠 [Relation to Algorithms]()
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These provide starting points for optimization.
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### [2nd Phase](): Optimality Check:
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# XI- 🧭 [Northwest Corner Method (Transportation]()
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It's a cornerstone of **Operational Research**, **Logistics**, and **Decision Science**.
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# XII - [ Northwest Corner Method - Exercise - Optimal Solution]()
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#### [Click here]() to access Theoretical and Pratical Material.
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#### [Click here](https://github.com/Quantum-Software-Development/Optimization-Simulation-MathModeling-LinearProgramming/blob/e6bee6582b53949aed266b384bb7ba6c15271480/class__10-Northwest%20Corner%20Method/class_9%20-%20Transportation%20Problem%20(Linear%20Programming).pdf) to access Theoretical and Pratical Material.
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#### [Click here]() and accessNorthwest Corner Method Exercises
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#### [Click here](https://github.com/Quantum-Software-Development/Optimization-Simulation-MathModeling-LinearProgramming/blob/e6bee6582b53949aed266b384bb7ba6c15271480/class__10-Northwest%20Corner%20Method/2-excel-Northwest%20Corner%20Method%20.md.md) and accessNorthwest Corner Method Exercises
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### - **Loop construction**: Adjustments involve $x_{31}$, $x_{32}$, $x_{22}$, and $x_{21}$, with a minimum adjustment of 10 units.
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- **Updated solution**:
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### - **Updated solution**:
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- $x_{31} = 10$, $x_{21} = 10$, $x_{22} = 130$, $x_{32} = 0$.
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- Total cost increases to **9820** due to an incorrect loop adjustment in manual calculations.
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### - **Updated solution**:
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### [Step 3](): Rechecking Optimality:
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- $x_{31} = 10$, $x_{21} = 10$, $x_{22} = 130$, $x_{32} = 0$.
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### - **Recalculated multipliers** (after correction)
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- $u =$, $v =$.
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- Total cost increases to **9820** due to an incorrect loop adjustment in manual calculations.
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### - **New reduced costs**:
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- $\bar{c}_{12} = -4$, $\bar{c}_{13} = -6$, $\bar{c}_{23} = -2$, $\bar{c}_{31} = 0$.
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### - Remaining negative reduced costs necessitate further iterations.
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<br>
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