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DI String Match.java
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48 lines (34 loc) · 840 Bytes
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Ques:
Given a string S that only contains "I" (increase) or "D" (decrease), let N = S.length.
Return any permutation A of [0, 1, ..., N] such that for all i = 0, ..., N-1:
If S[i] == "I", then A[i] < A[i+1]
If S[i] == "D", then A[i] > A[i+1]
Example 1:
Input: "IDID"
Output: [0,4,1,3,2]
Example 2:
Input: "III"
Output: [0,1,2,3]
Example 3:
Input: "DDI"
Output: [3,2,0,1]
Note:
1 <= S.length <= 10000
S only contains characters "I" or "D".
Soln:
class Solution {
public int[] diStringMatch(String S) {
int high=S.length();
int low=0;
int ar[]=new int[high+1];
for(int i=0;i<S.length();i++)
{
if(S.charAt(i)=='I')
ar[i]=low++;
else
ar[i]=high--;
}
ar[S.length()]=high;
return ar;
}
}