e6.py

#!/usr/bin/env python3

'''
The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural
numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred
natural numbers and the square of the sum.
'''

def sum_squares(n):
    return sum([x*x for x in range(n+1)])

def square_sum(n):
    return pow(sum([x for x in range(n+1)]), 2)

def main():
    n = 100
    result = square_sum(n) - sum_squares(n)
    print('Result: ', result)

if __name__ == '__main__':
    main()