How to create a counter within each run of my job

[madhavthaker]

Here is my code:

def job(count=0):
    print("I'm working on:", str(count))

schedule.every(10).seconds.do(job)

count = 0
while True:

    schedule.run_pending()
    time.sleep(1)
    count += 1

So, I'm confused about how i'd pass that count within my function. In the future, I plan to create a running list of live values that are being appended along with a counter and i'm not sure how i'd go about doing that

[talaniz]

I would say you could either update global variables or write out to a data source like a text file or database. While global variables are not encouraged, I was able to get the following example working (borrowed from the docs) which prints out the counter result every 10 seconds when the job is run--

import time

counter = 0

def job():
    print("I'm working...")
    global counter
    counter += 1
    print("Counter = {0}".format(counter))

result = schedule.every(10).seconds.do(job)

while True:

    schedule.run_pending()
    time.sleep(1)

[EEdLoh]

There's actually a super neat trick where modifications to mutable default parameters are persistent through multiple calls. Like if I had a program that read

def f(x=[0])
    print(x[0])
    x[0] += 1

for i in range(4):
    f()

I would get an output like

0
1
2
3

You could use this trick to keep a counter going on a job you had scheduled. Like:

def job(count=[0]):
    print("I'm working on:", str(count[0]))
    count[0] += 1

schedule.every(10).seconds.do(job)

while True:
    schedule.run_pending()
    time.sleep(1)