diff --git a/notebooks/B3. Logistic Regression - Analysis.ipynb b/notebooks/B3. Logistic Regression - Analysis.ipynb
index 4fdac2f..4b4e076 100755
--- a/notebooks/B3. Logistic Regression - Analysis.ipynb	
+++ b/notebooks/B3. Logistic Regression - Analysis.ipynb	
@@ -161,7 +161,7 @@
      "collapsed": false,
      "input": [
       "# we add a column which indicates (True/False) whether the interest rate is <= 12 \n",
-      "dfr['TF']=dfr['Interest.Rate']<=12\n",
+      "dfr['TF'] = dfr['Interest.Rate'] <= 12\n",
       "# inspect again\n",
       "dfr.head()\n",
       "# we see that the TF values are False as Interest.Rate is higher than 12 in all these cases"
@@ -355,9 +355,9 @@
       "# statsmodels requires us to add a constant column representing the intercept\n",
       "dfr['intercept']=1.0\n",
       "# identify the independent variables \n",
-      "ind_cols=['FICO.Score','Loan.Amount','intercept']\n",
+      "ind_cols = ['FICO.Score', 'Loan.Amount', 'intercept']\n",
       "logit = sm.Logit(dfr['TF'], dfr[ind_cols])\n",
-      "result=logit.fit()"
+      "result = logit.fit()"
      ],
      "language": "python",
      "metadata": {},
@@ -449,10 +449,10 @@
      "collapsed": false,
      "input": [
       "def pz(fico,amt,coeff):\n",
-      "  # compute the linear expression by multipyling the inputs by their respective coefficients.\n",
-      "  # note that the coefficient array has the intercept coefficient at the end\n",
-      "  z = coeff[0]*fico + coeff[1]*amt + coeff[2]\n",
-      "  return 1/(1+exp(-1*z))"
+      "    # compute the linear expression by multipyling the inputs by their respective coefficients.\n",
+      "    # note that the coefficient array has the intercept coefficient at the end\n",
+      "    z = coeff[0] * fico + coeff[1] * amt + coeff[2]\n",
+      "    return 1 / (1 + exp(-1 * z))"
      ],
      "language": "python",
      "metadata": {},
@@ -471,7 +471,7 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "pz(720,10000,coeff)"
+      "pz(720, 10000, coeff)"
      ],
      "language": "python",
      "metadata": {},
@@ -499,11 +499,11 @@
      "source": [
       "Now we are going to try (fico, amt) pairs as follows:\n",
       "\n",
-      "* 720,20000\n",
-      "* 720,30000\n",
-      "* 820,10000\n",
-      "* 820,20000 \n",
-      "* 820,30000 "
+      "* 720, 20000\n",
+      "* 720, 30000\n",
+      "* 820, 10000\n",
+      "* 820, 20000 \n",
+      "* 820, 30000 "
      ]
     },
     {
@@ -513,17 +513,17 @@
       "print(\"Trying multiple FICO Loan Amount combinations: \")\n",
       "print('----')\n",
       "print(\"fico=720, amt=10,000\")\n",
-      "print(pz(720,10000,coeff))\n",
+      "print(pz(720, 10000, coeff))\n",
       "print(\"fico=720, amt=20,000\")\n",
-      "print(pz(720,20000,coeff))\n",
+      "print(pz(720, 20000, coeff))\n",
       "print(\"fico=720, amt=30,000\")\n",
-      "print(pz(720,30000,coeff))\n",
+      "print(pz(720, 30000, coeff))\n",
       "print(\"fico=820, amt=10,000\")\n",
-      "print(pz(820,10000,coeff))\n",
+      "print(pz(820, 10000, coeff))\n",
       "print(\"fico=820, amt=20,000\")\n",
-      "print(pz(820,20000,coeff))\n",
+      "print(pz(820, 20000, coeff))\n",
       "print(\"fico=820, amt=30,000\")\n",
-      "print(pz(820,30000,coeff))\n"
+      "print(pz(820, 30000, coeff))\n"
      ],
      "language": "python",
      "metadata": {},
@@ -563,7 +563,7 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "pz(820,63000,coeff)"
+      "pz(820, 63000, coeff)"
      ],
      "language": "python",
      "metadata": {},
@@ -593,14 +593,14 @@
       "Try the following pairs of (fico, amt) values and plug them into the pz() function mimicing the syntax below.  What insight does this give you?\n",
       "\n",
       "\n",
-      "* 820,50000\n",
-      "* 820,60000\n",
-      "* 820,70000\n",
-      "* 820,63000\n",
-      "* 820,65000\n",
+      "* 820, 50000\n",
+      "* 820, 60000\n",
+      "* 820, 70000\n",
+      "* 820, 63000\n",
+      "* 820, 65000\n",
       "\n",
       "Place your cursor on the cell below.  Hit shift-enter to recreate the result.  \n",
-      "Then click Insert->Cell Below via the Insert menu dropdown.  This creates a new empty cell.\n",
+      "Then click Insert -> Cell Below via the Insert menu dropdown.  This creates a new empty cell.\n",
       "Now enter the pz() function with the next pair of values. Hit shift-enter.\n",
       "Repeat this till the end of the list of values.\n",
       "Answer the question above, if possible.\n",
@@ -611,7 +611,7 @@
      "cell_type": "code",
      "collapsed": false,
      "input": [
-      "pz(820,50000,coeff)"
+      "pz(820, 50000, coeff)"
      ],
      "language": "python",
      "metadata": {},