Exit an app

[espruino-discuss2]

Posted at 2022-09-14 by Hank

Lame question:
How do I exit my app and return to the user's watchface without needing to push the menu button?

[espruino-discuss2]

Posted at 2022-09-14 by rigrig

If you call load() without any arguments it will load the default clock.

---

Posted at 2022-09-14 by Hank

I actually tried that and it did not exit.
My code is

Bangle.loadWidgets();
Bangle.drawWidgets();

console.log('xxx');

load();
 

When starting the app it logs xxx and shows "Loading...".

---

Posted at 2022-09-15 by Hank

Ah ok, havin load() instead of load(); helps. But the IDE is claiming "missing semicolon" then :)

---

Posted at 2022-09-15 by @thyttan

Weird, I have

var standardMenu = {
  "" : {title : "Test intents",
        back : function() {load();}},
  // ...more code...,
};

Bangle.loadWidgets();
E.showMenu(standardMenu);

where I use a semicolon behind load() and that works to take me to the clock when I press the red software back button in the app.

---

Posted at 2022-09-17 by HughB

I think you have to call it as the payload of a timeout. 20ms delay will do.
There is another thread about this as it is a question I once asked when I hit the same problem.

---

Posted at 2022-09-21 by @gfwilliams

I think the issue is the difference between:

var standardMenu = {
  "" : {title : "Test intents",
        back : function() {load();}},
};
// and
var standardMenu = {
  "" : {title : "Test intents",
        back : load,
  // ...more code...,
};

The functions in menus get called with the menu itself as an argument, so you're effectivaly calling load({...}) and it can't find a file called "{...}" so it doesn't load anything