Adafruit 8x8 LED Backpacks

[espruino-discuss2]

Posted at 2015-11-07 by chalkers

I purchased this Small 1.2" 8x8 Ultra Bright Square White LED Matrix + Backpack.

I got it working with an Arduino to make sure everything is wired up correctly and it does work.

https://vine.co/v/eLx5pq7zAhK

I believe it uses the MAX7219 driver but can't get it to work. Adafruit uses I2C and the Espruino library uses SPI.

Is there any raw I2C code I can use to test it out. I've wired up the - + to GND and 5v, and C to B6 and D to B7.

I2C1.setup({scl:B6, sda:B7});

Thanks

[gfwilliams]

Posted at 2015-11-07 by @gfwilliams

Hi, I know it says MAX7219 in the description, but it looks from the picture on the Adafruit page like it's actually something else... I think HT16K33.

Adafruit's driver looks quite simple though, so you should be able to get up and running quite quick...

I2C1.setup({scl:B6, sda:B7});
I2C1.writeTo(0x70, 0x21); // turn on oscillator
I2C1.writeTo(0x70, 0x81); // disp on
I2C1.writeTo(0x70, 0xE0 | 15); // brightness 15

// not sure about this, you may need 16,8,1
var g = Graphics.createArrayBuffer(8,8,2); 
g.flip = function() {
  I2C1.writeTo(0x70, 0, g.buffer); 
};


g.drawLine(0,0,8,8);
g.flip();

[espruino-discuss2]

Posted at 2015-11-07 by chalkers

Thank you so much Gordon! I am so happy to see something come alive!

I used this:

var g = Graphics.createArrayBuffer(16,8,1); 

To get this result -

Is that what you were expecting?

Also, I'm giving a talk on the state of JavaScript and IoT at Node.js Interactive and at FluentConf next year and I'm showcasing the Pico along with other things!

[gfwilliams]

Posted at 2015-11-07 by @gfwilliams

That's great! It's almost what I was hoping for, but it looks a bit like somehow it's wrapped around so one of the lines is in the wrong place... I was expecting just a diagonal line.

Maybe try some other things with graphics:

g.clear();
g.drawRect(0,0,7,7);
g.flip();

g.clear();
g.drawString("Hi");
g.flip();

and see if it's doing the right thing. It might be we have to fiddle with it a bit to get everything lined up.

Maybe try one of these commands in flip instead and see if it fixes it:

I2C1.writeTo(0x70, 1, g.buffer); 
I2C1.writeTo(0x70, 2, g.buffer); 
I2C1.writeTo(0x70, 7, g.buffer); 
I2C1.writeTo(0x70, 14, g.buffer); 

When that's done we should turn it into a module :)

It'll be great if you included the Pico in your talks too - thanks! Let me know if i can help out at all.

[espruino-discuss2]

Posted at 2015-11-07 by chalkers

The horse shoe looking one was I2C1.writeTo(0x70, 0, g.buffer);

I2C1.writeTo(0x70, 1, g.buffer); and I2C1.writeTo(0x70, 7, g.buffer); were off.

I2C1.writeTo(0x70, 2, g.buffer); and I2C1.writeTo(0x70, 14, g.buffer); created the L shape.

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[espruino-discuss2]

Posted at 2015-11-07 by chalkers

It seems 0,0 starts at 0,1 or 1,0.

[espruino-discuss2]

Posted at 2015-11-07 by chalkers

PaintYourDragon from adafruit said this on Twitter:

It's wired that way for routing reasons; need to ROL or ROR (forget
which).

https://twitter.com/paintyourdragon/status/663086330834907136

I don't understand what that means :)

[espruino-discuss2]

Posted at 2015-11-08 by HaraldK

ROR is ROtate Right. ROL is ROtate Left.
Difference to a normal shift is that in a shift all bits move one bit position. The leftmost in a shift left or rightmost in a shift right usually gets a 0.
In a rotation the bits move in a circle: in a left shift bit 7 moves into bit 0.
See here: https://en.wikipedia.org/wiki/Bitwise_operation#Rotate_no_carry

[espruino-discuss2]

Posted at 2015-11-08 by chalkers

So do I have to do a bit wise operation on the buffer?

[gfwilliams]

Posted at 2015-11-09 by @gfwilliams

Thanks for the pics - that really clears it up!

It's a bit hacky of them to fiddle the wiring like that!

So yes, looks like you have to do a bitwise operation - but it's not too painful. Something like:

// rotate right
I2C1.writeTo(0x70, 0, 
  (new Uint8Array(g.buffer)).map(function(a) { return (a>>1)||(a<<7); }));
// or you might need to rotate left
I2C1.writeTo(0x70, 0, 
  (new Uint8Array(g.buffer)).map(function(a) { return (a>>7)||(a<<1); }));

[espruino-discuss2]

Posted at 2015-11-10 by chalkers

Thanks for getting me this far!

return (a>>1)||(a<<7); 

This rotated the pixels correctly except for one last issue...

I can draw a line, I can set a pixel anywhere in the grid.

If the left most x is on 0 and it doesn't share the row with another pixel it will show up. If it does share with another pixel, it switches off.

g.clear();
//face top
g.setPixel(2,0);
g.setPixel(3,0);
g.setPixel(4,0);
g.setPixel(5,0);
g.setPixel(1,1);
g.setPixel(6,1);

//face left
g.setPixel(0,2);
g.setPixel(0,3); // Won't show because of eyes on 2 and 5.
g.setPixel(0,4);
g.setPixel(0,5);

//eyes
g.setPixel(2,3);
g.setPixel(5,3);

//face right
//g.setPixel(7,2);
//g.setPixel(7,3);
//g.setPixel(7,4);
//g.setPixel(7,5);

//face bottom
g.setPixel(2,7);
g.setPixel(3,7);
g.setPixel(4,7);
g.setPixel(5,7);
g.setPixel(1,6);
g.setPixel(6,6);

g.flip();

If I comment out the eyes the left most pixel will show:

g.clear();
//face top
g.setPixel(2,0);
g.setPixel(3,0);
g.setPixel(4,0);
g.setPixel(5,0);
g.setPixel(1,1);
g.setPixel(6,1);

//face left
g.setPixel(0,2);
g.setPixel(0,3); // Won't show because of eyes on 2 and 5.
g.setPixel(0,4);
g.setPixel(0,5);


//eyes
//g.setPixel(2,3);
//g.setPixel(5,3);

//face right
//g.setPixel(7,2);
//g.setPixel(7,3);
//g.setPixel(7,4);
//g.setPixel(7,5);

//face bottom
g.setPixel(2,7);
g.setPixel(3,7);
g.setPixel(4,7);
g.setPixel(5,7);
g.setPixel(1,6);
g.setPixel(6,6);

g.flip();

[espruino-discuss2]

Posted at 2015-11-10 by chalkers

I created a git repo with tests and this is the function we got to get it working:

module.exports = function rotate(value) {
    var rotated = value >> 1;
    // Check to see if the first bit was set...
    if (1 & value) {
    	//...flip the furthest bit on.
    	rotated += (1 << 7);
    }
    return rotated;
};

[espruino-discuss2]

Posted at 2015-11-10 by chalkers

@gordon How do I go about contributing modules to the Espruino project?

[gfwilliams]

Posted at 2015-11-10 by @gfwilliams

Sorry, I made a really stupid typo I'm afraid...

return (a>>1)||(a<<7); 

should be:

return (a>>1)|(a<<7); 

|| is a logical OR, but | is a binary one that works on all bits. Glad you got it sorted though!

There's a bit of info on writing and submitting modules here: http://www.espruino.com/Writing+Modules

For displays, we generally just just create an exports.connect function and then return the Graphics object we created with flip() function added... then everything works the same way.

[espruino-discuss2]

Posted at 2016-05-25 by Kylir

Guys I would like to thank you for this post! Now everything makes sense!

I started to fiddle with a small 8x8 LED matrix from Adafruit and I wasn't able to understand why the first line was "broken".

@chalkers did you manage to write a module for the 8x8? I have the same goal.

Thanks again!

[espruino-discuss2]

Posted at 2016-05-25 by chalkers

Hey Kylir

I created an NPM module...you can check it out here:
https://www.npmjs.com/package/espruino-adafruit-led-backpack

Feel free to contribute additional functionality via GitHub :)

But I have the basics of drawing implemented :)

Regards
Andrew

[gfwilliams]

Posted at 2016-05-25 by @gfwilliams

@chalkers thanks! You know you can use Espruino's built-in graphics library, rather than using your own?

var g = Graphics.createArrayBuffer(8,8,1);
// g.buffer is now a Uint8Array with 8 bytes, one for each row
// You might even be able to use your existing code with matrix.drawBitmap(g.buffer)

It's got rotation, fonts, lines, etc etc.

[espruino-discuss2]

Posted at 2016-05-25 by chalkers

The module uses a similar API to what the arduino library had for the backpack. It uses the graphics API in the module :)

[espruino-discuss2]

Posted at 2016-06-07 by pedesen

This is pretty awesome, guys! I recently bought the 16x8 backpack and I'd be happy to extend the code and test it with that backpack (if I find the time).

[espruino-discuss2]

Posted at 2016-06-16 by pedesen

I created a pull request for it \o/

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