queue.add runs the future immediately, why?

[burekas7]

@rknell

Hi,

What could be the reason that when I add a Future to the queue using add, it immediately runs the Future?

I didn’t put an await before queue.add.

I want to collect all of them first, and only when I run onComplete, I want them to execute one after another.

For example:

  static Future<void> Function() createOfflineQueueTask({
    required Future<void> Function() apiCall,
  }) {
    return () async {
      print("Executing offline API call...");
      await apiCall();
      print("Finished executing offline API call...");
    };
  }

apiCall is Future<T?> Function()

queue.add(createOfflineQueueTask(apiCall: apiCall);

And when I want to run them:

queue.onComplete.then((_) {
      remainingItemsStream.close();
      queue?.dispose();
    });

But thequeue.add runs them immediately instead before running the onComplete, why?