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Description
Chapter
Types and Traits
Guideline Title
Do not compare raw pointers to allocations with different provenance
Category
Required
Status
Draft
Release Begin
unclear
Release End
latest
FLS Paragraph ID
fls_bw8zutjcteki
Decidability
Decidable
Scope
System
Tags
surprising-behavior
Amplification
Do not compare raw pointers to allocations with different provenances for equality, inequality, or ordering.
Pointer comparisons are permitted only when both pointers are guaranteed to reference the same allocation or subobject.
Code shall not rely on:
- Layout of variables in memory
- Assumed field layout of structs without
repr(C)orrepr(packed) - Outcomes of pointer arithmetic across allocation boundaries
Exception(s)
No response
Rationale
Although raw pointer comparison is not itself undefined behavior;
comparing pointers with different provenance can give surprising results which might cause logic errors,
portability issues, and inconsistent behavior across different optimization levels, builds, or platforms.
Specifically, the result of comparing pointers with different providence is guaranteed to be the comparison of the pointer addresses.
However, the addresses that are selected for allocations is unspecified.
Pointer equality or ordering is only meaningful when both pointers are derived from the same allocated object or block of memory.
Comparisons across unrelated allocations are semantically meaningless and must be avoided.
Non-Compliant Example - Prose
This noncompliant example allocates two local u32 variables on the stack.
The order of these two variables in memory is unspecified behavior.
The code then creates a raw pointer to v2 and a raw pointer to v1.
Adds the address stored in v1 to 1 × size_of::<u32>() = 4 bytes using wrapping_offset which:
- ignores provenance
- may produce an arbitrary, invalid, or meaningless pointer
- is always allowed but does not guarantee the pointer points to anything valid
Comparing two values of raw pointer types compares the addresses of the values.
This code then compares ptr (a pointer to v2) with ptr2 (a pointer to v1 + 4 bytes).
Because the stack layout is unspecified behavior, the result of this comparison depends on how the compiler the memory layout for v1 and v2 on the stack.
The result may change across:
- compiler versions
- optimization levels
- targets
- small code changes
- builds with or without link-time optimization
This noncompliant example does not contain undefined behavior (because no pointer is dereferenced) but it does depend on unspecified behavior, meaning that the program is valid, but the results are undefined.
Non-Compliant Example - Code
pub fn raw_ptr_comparison(){
let v1: u32 = 1;
let v2: u32 = 2;
let ptr = &v2 as *const u32;
let ptr2 = (&v1 as *const u32).wrapping_offset(1);
if ptr == ptr2 {
println!("Same");
}
else{
println!("Not the same");
}
}
Compliant Example - Prose
This compliant example creates a mutable array of 16 bytes on the stack where all bytes are zero-initialized.
The entire array is one contiguous allocation.
The code creates a raw pointer p of type *const u8 to the first element of the array (that is, buf[0]).
The ptr p points at the start of the allocation.
The code then uses pointer arithmetic to compute a pointer q which points 4 elements past p.
Because the element type is u8, this means “4 bytes past p”.
The pointer arithmetic is safe as long as the resulting pointer stays within the same allocation (it does).
This is permitted because pointer arithmetic is allowed within the same allocated object.
Finally, the code compares the numerical address values of p and q.
Pointer comparison is always allowed.
Comparing pointers from the same allocation is meaningful and defined.
Because p points to the beginning and q to a later part of the same array, same_block becomes true.
Compliant Example - Code
let mut buf = [0u8; 16];
let p = buf.as_ptr();
let q = unsafe { p.add(4) };
let same_block = p < q; // ok: comparison within same allocation
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