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$ hashsum --b2sum -l 0 /dev/null
786a02f742015903c6c6fd852552d272912f4740e15847618a86e217f71f5419d25e1031afee585313896444934eb04b903a685b1448b755d56f701afe9be2ce /dev/null
$ hashsum --b2sum -l 8 /dev/null
786a02f742015903c6c6fd852552d272912f4740e15847618a86e217f71f5419d25e1031afee585313896444934eb04b903a685b1448b755d56f701afe9be2ce /dev/null
$ cksum -a blake2b -l 0 /dev/null
BLAKE2b (/dev/null) = 786a02f742015903c6c6fd852552d272912f4740e15847618a86e217f71f5419d25e1031afee585313896444934eb04b903a685b1448b755d56f701afe9be2ce
$ cksum -a blake2b -l 8 /dev/null
BLAKE2b-8 (/dev/null) = 2e
Solution: Just drop the duplicated interface.