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Time - Anaya #22
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Time - Anaya #22
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| @@ -1,88 +1,200 @@ | ||
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| # Defines a node in the singly linked list | ||
| class Node | ||
| attr_reader :data # allow external entities to read value but not write | ||
| attr_accessor :next # allow external entities to read or write next node | ||
| attr_accessor :previous | ||
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| def initialize(value, next_node = nil) | ||
| @data = value | ||
| @next = next_node | ||
| @previous = previous | ||
| end | ||
| end | ||
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| # Defines the singly linked list | ||
| class LinkedList | ||
| def initialize | ||
| @head = nil # keep the head private. Not accessible outside this class | ||
| @tail = nil | ||
| end | ||
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| # method to add a new node with the specific data value in the linked list | ||
| # insert the new node at the beginning of the linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(1) | ||
| # Space Complexity: O(1) | ||
| def add_first(value) | ||
| raise NotImplementedError | ||
| if @head.nil? | ||
| @head = @tail = Node.new(value) | ||
| else | ||
| new_node = Node.new(value, @head) | ||
| @head.previous = new_node | ||
| @head = new_node | ||
| end | ||
| end | ||
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| # method to find if the linked list contains a node with specified value | ||
| # returns true if found, false otherwise | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def search(value) | ||
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| raise NotImplementedError | ||
| return false if @head.nil? | ||
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| pointer = @head | ||
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| until pointer.next.nil? | ||
| if pointer.data == value || pointer.next.data == value | ||
| return true | ||
| else | ||
| pointer = pointer.next | ||
| end | ||
| end | ||
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| return false | ||
| end | ||
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| # method to return the max value in the linked list | ||
| # returns the data value and not the node | ||
| def find_max | ||
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| raise NotImplementedError | ||
| return nil if @head.nil? | ||
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| max = @head.data | ||
| pointer = @head | ||
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| while !pointer.nil? | ||
| if pointer.data > max | ||
| max = pointer.data | ||
| end | ||
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| pointer = pointer.next | ||
| end | ||
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| return max | ||
| end | ||
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| # method to return the min value in the linked list | ||
| # returns the data value and not the node | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def find_min | ||
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| raise NotImplementedError | ||
| return nil if @head.nil? | ||
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| min = @head.data | ||
| pointer = @head | ||
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| while !pointer.nil? | ||
| if pointer.data < min | ||
| min = pointer.data | ||
| end | ||
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| pointer = pointer.next | ||
| end | ||
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| return min | ||
| end | ||
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| # method that returns the length of the singly linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def length | ||
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| raise NotImplementedError | ||
| return 0 if @head.nil? | ||
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| pointer = @head | ||
| count = 1 | ||
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| until pointer.next.nil? | ||
| count += 1 | ||
| pointer = pointer.next | ||
| end | ||
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| return count | ||
| end | ||
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| # method that returns the value at a given index in the linked list | ||
| # index count starts at 0 | ||
| # returns nil if there are fewer nodes in the linked list than the index value | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def get_at_index(index) | ||
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| raise NotImplementedError | ||
| pointer = @head | ||
| node_index = 0 | ||
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| until pointer.nil? | ||
| if node_index == index | ||
| return pointer.data | ||
| else | ||
| node_index += 1 | ||
| end | ||
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| pointer = pointer.next | ||
| end | ||
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| return nil | ||
| end | ||
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| # method to print all the values in the linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def visit | ||
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| raise NotImplementedError | ||
| pointer = @head | ||
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| while !pointer.nil? | ||
| puts pointer.data | ||
| pointer = pointer.next | ||
| end | ||
| end | ||
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| # method to delete the first node found with specified value | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
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| def delete(value) | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 , but the space complexity is O(1) since you're not creating a new list. |
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| raise NotImplementedError | ||
| return nil if @head.nil? | ||
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| pointer = @head | ||
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| while !pointer.nil? | ||
| if pointer.data == value | ||
| if pointer == @head | ||
| @head = pointer.next | ||
| end | ||
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| if pointer == @tail | ||
| @tail = pointer.previous | ||
| end | ||
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| if !pointer.next.nil? | ||
| pointer.next.previous = pointer.previous | ||
| end | ||
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| if !pointer.previous.nil? | ||
| pointer.previous.next = pointer.next | ||
| end | ||
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| return | ||
| end | ||
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| pointer = pointer.next | ||
| end | ||
| end | ||
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| # method to reverse the singly linked list | ||
| # note: the nodes should be moved and not just the values in the nodes | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(1) | ||
| def reverse | ||
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| raise NotImplementedError | ||
| pointer = @head | ||
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| while !pointer.nil? | ||
| holder = pointer.previous | ||
| pointer.previous = pointer.next | ||
| pointer.next = holder | ||
| pointer = pointer.previous | ||
| end | ||
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| holder = @head | ||
| @head = @tail | ||
| @tail = holder | ||
| end | ||
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👍