-
Notifications
You must be signed in to change notification settings - Fork 48
Time - Haben #35
New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
base: master
Are you sure you want to change the base?
Time - Haben #35
Changes from all commits
26a4f89
f3b68cc
c82e0e4
9fada2f
a018f77
be9e04c
557f56c
File filter
Filter by extension
Conversations
Jump to
Diff view
Diff view
There are no files selected for viewing
| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -1,161 +1,270 @@ | ||
| # frozen_string_literal: true | ||
|
|
||
| # Defines a node in the singly linked list | ||
| class Node | ||
| attr_reader :data # allow external entities to read value but not write | ||
| attr_accessor :next # allow external entities to read or write next node | ||
| attr_accessor :previous | ||
|
|
||
| def initialize(value, next_node = nil) | ||
| @data = value | ||
| @next = next_node | ||
| @previous = previous | ||
| end | ||
| end | ||
|
|
||
| # Defines the singly linked list | ||
| class LinkedList | ||
| def initialize | ||
| @head = nil # keep the head private. Not accessible outside this class | ||
| end | ||
| def initialize | ||
| @head = nil # keep the head private. Not accessible outside this class | ||
| @tail = nil | ||
| end | ||
|
|
||
| # method to add a new node with the specific data value in the linked list | ||
| # insert the new node at the beginning of the linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def add_first(value) | ||
| raise NotImplementedError | ||
| # method to add a new node with the specific data value in the linked list | ||
| # insert the new node at the beginning of the linked list | ||
| # Time Complexity:O(1) | ||
| # Space Complexity:O(1) | ||
| def add_first(value) | ||
| if @head.nil? | ||
| @head = @tail = Node.new(value) | ||
| else | ||
| new_node = Node.new(value, @head) | ||
| @head = new_node | ||
| end | ||
| end | ||
|
|
||
| # method to find if the linked list contains a node with specified value | ||
| # returns true if found, false otherwise | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def search(value) | ||
| raise NotImplementedError | ||
| end | ||
| # method to find if the linked list contains a node with specified value | ||
| # returns true if found, false otherwise | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def search(value) | ||
|
Comment on lines
+38
to
+40
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 , the space complexity is O(1) |
||
| return false if @head.nil? | ||
|
|
||
| # method to return the max value in the linked list | ||
| # returns the data value and not the node | ||
| def find_max | ||
| raise NotImplementedError | ||
| end | ||
| current = @head | ||
| return true if current.data == value | ||
|
|
||
| # method to return the min value in the linked list | ||
| # returns the data value and not the node | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def find_min | ||
| raise NotImplementedError | ||
| while (current = current.next) | ||
|
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Clever use of the |
||
| return true if current.data == value | ||
| end | ||
| false | ||
| end | ||
|
|
||
| # method to return the max value in the linked list | ||
| # returns the data value and not the node | ||
| def find_max | ||
| return nil if @head.nil? | ||
|
|
||
| # method that returns the length of the singly linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def length | ||
| raise NotImplementedError | ||
| end | ||
| max = @head.data | ||
| current = @head | ||
|
|
||
| # method that returns the value at a given index in the linked list | ||
| # index count starts at 0 | ||
| # returns nil if there are fewer nodes in the linked list than the index value | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def get_at_index(index) | ||
| raise NotImplementedError | ||
| while (current = current.next) | ||
| max = current.data if current.data > max | ||
| end | ||
|
|
||
| # method to print all the values in the linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def visit | ||
| raise NotImplementedError | ||
| end | ||
| max | ||
| end | ||
|
|
||
| # method to delete the first node found with specified value | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def delete(value) | ||
| raise NotImplementedError | ||
| end | ||
| # method to return the min value in the linked list | ||
| # returns the data value and not the node | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def find_min | ||
|
Comment on lines
+69
to
+71
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 , the space complexity is O(1) because you're not creating a new list. |
||
| return nil if @head.nil? | ||
|
|
||
| # method to reverse the singly linked list | ||
| # note: the nodes should be moved and not just the values in the nodes | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def reverse | ||
| raise NotImplementedError | ||
| min = @head.data | ||
| current = @head | ||
| while (current = current.next) | ||
| min = current.data if current.data < min | ||
| end | ||
| min | ||
| end | ||
|
|
||
| # method that returns the length of the singly linked list | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def length | ||
|
Comment on lines
+83
to
+85
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 , the space complexity is O(1) because you're not creating a new list. |
||
| return 0 if @head.nil? | ||
|
|
||
| ## Advanced Exercises | ||
| # returns the value at the middle element in the singly linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def find_middle_value | ||
| raise NotImplementedError | ||
| end | ||
| count = 1 | ||
| current = @head | ||
|
|
||
| # find the nth node from the end and return its value | ||
| # assume indexing starts at 0 while counting to n | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def find_nth_from_end(n) | ||
| raise NotImplementedError | ||
| while (current = current.next) | ||
| count += 1 | ||
| end | ||
| count | ||
| end | ||
|
|
||
| # checks if the linked list has a cycle. A cycle exists if any node in the | ||
| # linked list links to a node already visited. | ||
| # returns true if a cycle is found, false otherwise. | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def has_cycle | ||
| raise NotImplementedError | ||
| # method that returns the value at a given index in the linked list | ||
| # index count starts at 0 | ||
| # returns nil if there are fewer nodes in the linked list than the index value | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def get_at_index(index) | ||
|
Comment on lines
+100
to
+102
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. The space complexity is O(1) because you're not creating a new list. |
||
| return nil if @head.nil? | ||
|
|
||
| current = @head | ||
| index.times do | ||
| current = current.next | ||
| end | ||
|
Comment on lines
+106
to
108
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. What if the list is shorter than |
||
| current.data | ||
| end | ||
|
|
||
| # method to print all the values in the linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def visit | ||
|
Comment on lines
+113
to
+115
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 Space and time complexity ❓ |
||
| return nil if @head.nil? | ||
|
|
||
| # Additional Exercises | ||
| # returns the value in the first node | ||
| # returns nil if the list is empty | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def get_first | ||
| raise NotImplementedError | ||
| current = @head | ||
| print @head.data.to_s + '-->' | ||
| while (current = current.next) | ||
| print current.data.to_s + '-->' | ||
| end | ||
| end | ||
|
|
||
| # method that inserts a given value as a new last node in the linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def add_last(value) | ||
| raise NotImplementedError | ||
| end | ||
| # method to delete the first node found with specified value | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def delete(value) | ||
|
Comment on lines
+126
to
+128
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 , the space complexity is O(1) because you're not creating a new list. |
||
| return false if @head.nil? | ||
|
|
||
| # method that returns the value of the last node in the linked list | ||
| # returns nil if the linked list is empty | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def get_last | ||
| raise NotImplementedError | ||
| current = @head | ||
| if current.data == value | ||
| @head = current.next | ||
| else | ||
| until current.next.nil? | ||
| if current.next.data == value | ||
| current.next = current.next.next | ||
| return | ||
| end | ||
| current.next.next = nil if current.next.next == @tail && current.next.next.data == value | ||
| current = current.next | ||
| end | ||
| end | ||
| end | ||
|
|
||
| # method to insert a new node with specific data value, assuming the linked | ||
| # list is sorted in ascending order | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def insert_ascending(value) | ||
| raise NotImplementedError | ||
| # method to reverse the singly linked list | ||
| # note: the nodes should be moved and not just the values in the nodes | ||
| # Time Complexity: o(n) | ||
| # Space Complexity: O(n) | ||
| # def reverse | ||
| # current = @head | ||
| # while current != nil | ||
| # temp = current.previous | ||
| # current.previous = current.next | ||
| # current.next = temp | ||
| # current = current.previous | ||
| # end | ||
| # temp = @head | ||
| # @head = @tail | ||
| # @tail = temp | ||
| # end | ||
|
|
||
| def reverse | ||
|
Comment on lines
+148
to
+163
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 , the space complexity is O(1) because you're not creating a new list. |
||
| current = @head | ||
| previous = nil | ||
| while current != nil | ||
| temp = current.next # save state | ||
| current.next = previous # update the link | ||
| previous = current | ||
| current = temp | ||
| end | ||
| @head = previous | ||
| end | ||
|
|
||
| # Helper method for tests | ||
| # Creates a cycle in the linked list for testing purposes | ||
| # Assumes the linked list has at least one node | ||
| def create_cycle | ||
| return if @head == nil # don't do anything if the linked list is empty | ||
|
|
||
| # navigate to last node | ||
| current = @head | ||
| while current.next != nil | ||
| current = current.next | ||
| end | ||
| ## Advanced Exercises | ||
| # returns the value at the middle element in the singly linked list | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def find_middle_value | ||
| raise NotImplementedError | ||
| | ||
| # slowPointer = @head | ||
| # fastPointer = @head | ||
| | ||
| # if @head !=nil | ||
| # while (fastPointer !=nil && fastPointer.next !=nil) | ||
| # fastPointer = fastPointer.next.next | ||
| # slowPointer = slowPointer.next | ||
| # end | ||
| # end | ||
| # # print("The middle element is: ", slow_ptr.data) | ||
| # slowPointer.data | ||
| end | ||
|
|
||
| # find the nth node from the end and return its value | ||
| # assume indexing starts at 0 while counting to n | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def find_nth_from_end(n) | ||
| raise NotImplementedError | ||
| end | ||
|
|
||
| # checks if the linked list has a cycle. A cycle exists if any node in the | ||
| # linked list links to a node already visited. | ||
| # returns true if a cycle is found, false otherwise. | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def has_cycle | ||
| raise NotImplementedError | ||
| end | ||
|
|
||
| # Additional Exercises | ||
| # returns the value in the first node | ||
| # returns nil if the list is empty | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def get_first | ||
|
Comment on lines
+216
to
+218
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 , space & time complexity? |
||
| @head ? @head.data : nil | ||
| end | ||
|
|
||
| current.next = @head # make the last node link to first node | ||
| # method that inserts a given value as a new last node in the linked list | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def add_last(value) | ||
|
Comment on lines
+223
to
+225
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 , Space complexity is O(1) |
||
| new_node = Node.new(value) | ||
| if @head.nil? | ||
| add_first(new_node.data) | ||
| return | ||
| end | ||
| current = @head | ||
| current = current.next until current.next.nil? | ||
| current.next = new_node | ||
| new_node.next = nil | ||
| end | ||
|
|
||
| # method that returns the value of the last node in the linked list | ||
| # returns nil if the linked list is empty | ||
| # Time Complexity: O(n) | ||
| # Space Complexity: O(n) | ||
| def get_last | ||
|
Comment on lines
+239
to
+241
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 , the space complexity is O(1) because you're not creating a new list. |
||
| return nil if @head.nil? | ||
|
|
||
| current = @head | ||
| current = current.next until current.next.nil? | ||
| current.data | ||
| end | ||
|
|
||
| # method to insert a new node with specific data value, assuming the linked | ||
| # list is sorted in ascending order | ||
| # Time Complexity: ? | ||
| # Space Complexity: ? | ||
| def insert_ascending(value) | ||
| raise NotImplementedError | ||
| end | ||
|
|
||
| # Helper method for tests | ||
| # Creates a cycle in the linked list for testing purposes | ||
| # Assumes the linked list has at least one node | ||
| def create_cycle | ||
| return if @head.nil? # don't do anything if the linked list is empty | ||
|
|
||
| | ||
| # navigate to last node | ||
| current = @head | ||
| current = current.next until current.next.nil? | ||
| | ||
| current.next = @head # make the last node link to first node | ||
| end | ||
| end | ||
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
👍