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109 changes: 82 additions & 27 deletions binary_search_tree/tree.py
Original file line number Diff line number Diff line change
@@ -1,59 +1,114 @@
class TreeNode:
def __init__(self, key, val = None):
def __init__(self, key, val=None):
if val == None:
val = key

self.key = key
self.value = val
self.left = None
self.right = None



class Tree:
def __init__(self):
self.root = None

# Time Complexity:
# Space Complexity:
# Time Complexity: O(log n)
# Space Complexity: O(1)
def add_helper(self, current, key, value):
Comment on lines +14 to +16

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👍 Since this is recursive the space complexity is O(log n) assuming the tree is balanced and O(n) otherwise.

if current is None:
return TreeNode(key, value)
if current.key >= key:
current.left = self.add_helper(current.left, key, value)
else:
current.right = self.add_helper(current.right, key, value)
return current

def add(self, key, value = None):
pass
if self.root == None:
self.root = TreeNode(key, value)
else:
self.add_helper(self.root, key, value)

# Time Complexity:
# Space Complexity:
# Time Complexity: O(log n)
# Space Complexity: O(1)
def find(self, key):
Comment on lines +31 to 33

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👍

pass
current = self.root
while current:
if current.key == key:
return current.value
elif current.key > key:
current = current.left
else:
current= current.right

# Time Complexity: O(n)
# Space Complexity: O(1)

# Time Complexity:
# Space Complexity:
def inorder_helper(self, current, values_list):
Comment on lines +43 to +46

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👍 , but since you're building a list of node values, the space complexity is O(n)

if not current:
return values_list
object = {"key": current.key, "value": current.value}

self.inorder_helper(current.left, values_list)
values_list.append(object)
self.inorder_helper(current.right, values_list)

return values_list

def inorder(self):
pass
values_list = []
return self.inorder_helper(self.root, values_list)

# Time Complexity: O(n)
# Space Complexity: O(1)

def preorder_helper(self, current_node, values_list):
Comment on lines +61 to +64

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👍 Same issue with space complexity

if not current_node:
return values_list
object = {"key": current_node.key, "value": current_node.value}

values_list.append(object)
self.preorder_helper(current_node.left, values_list)
self.preorder_helper(current_node.right, values_list)
return values_list

# Time Complexity:
# Space Complexity:
def preorder(self):
pass
values_list = []
return self.preorder_helper(self.root, values_list)

# Time Complexity: O(n)
# Space Complexity: O(1)
def postorder_helper(self, current_node, values_list):
Comment on lines +78 to +80

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👍 Same issue with space complexity

if not current_node:
return values_list
object = {"key": current_node.key, "value": current_node.value}

self.postorder_helper(current_node.left, values_list)
self.postorder_helper(current_node.right, values_list)
values_list.append(object)
return values_list

# Time Complexity:
# Space Complexity:
def postorder(self):
pass
values_list = []
return self.postorder_helper(self.root, values_list)


# Time Complexity:
# Space Complexity:
def height(self):
pass
# Time Complexity: O(n)
# Space Complexity: O(n)
def height_helper(self, current_node):
Comment on lines +95 to +97

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👍 If the tree is balanced this is O(log n) for space complexity and O(n) otherwise.

if not current_node:
return 0

return max(self.height_helper(current_node.left), self.height_helper(current_node.right)) + 1
def height(self):
return self.height_helper(self.root)


# # Optional Method
# # Time Complexity:
# # Space Complexity:
def bfs(self):
pass




# # Useful for printing
def to_s(self):
return f"{self.inorder()}"
return f"{self.inorder()}"
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