Added tictactoe program

tictactoe/tictactoe.py

@@ -0,0 +1,104 @@
+# Make a TIC TAC TOE game
+from random import randint
+from IPython.display import clear_output
+
+# Let user select what they want
+usr_input = input("Enter your choice 'X' or 'O': ").upper()
+if usr_input == 'X':
+    computer_input = 'O'
+
+elif usr_input == 'O':
+    computer_input = 'X'
+
+# Game will run until user does not enters no
+while usr_input!='NO':
+    computer_number=0
+    if usr_input == 'X':
+        computer_input = 'O'
+        print('You are now X \nMake move')
+    elif usr_input == 'O':
+        computer_input = 'X'
+        print('You are now O \nMake move')
+
+    #Dictonary
+    # Make every position in board as blank space
+    d = {1:' ',2:' ',3:' ',4:' ',5:' ',6:' ',7:' ',8:' ',9:' ' }
+
+    # Board
+    line = ' {0} | {1} | {2} \n-----------\n {3} | {4} | {5}\n----------- \n {6} | {7} | {8}'
+
+    # Condition becomes true if user type no
+    condition = False
+    print(line.format(1,2,3,4,5,6,7,8,9))
+    while condition != True:
+        # Take input from user to represent 'X' or 'O' on board
+        usr_number = int(input('Enter number: '))
+
+        # If user puts number at which there is already a 'X' or 'O' then user must enter number again
+        while computer_number==usr_number or d[usr_number]=='O' or d[usr_number]=='X':
+            print('Please enter other number')
+            usr_number = int(input('Enter number: '))
+        if d[usr_number] == ' ':
+            d[usr_number] = usr_input
+
+        #clear screen here
+        clear_output()
+
+        # Print the board
+        print(line.format(d[1],d[2],d[3],d[4],d[5],d[6],d[7],d[8],d[9])+'\n')
+
+        # Condition to check if user has won or not
+        # Check win condition on rows
+        if (d[1]==d[2]==d[3]==usr_input) or (d[4]==d[5]==d[6]==usr_input)or (d[7]==d[8]==d[9]==usr_input):
+            print('You won!!')
+            break
+
+        # Check win condition on column
+        elif (d[1]==d[4]==d[7]==usr_input) or (d[2]==d[5]==d[8]==usr_input) or (d[3]=='X' and d[6]=='X' and d[9]==usr_input):
+            print('You won!!')
+            break
+
+        # Check win condition on diagonals
+        elif (d[7]==d[5]==d[3]==usr_input) or (d[1]==d[5]==d[9]==usr_input):    
+            print('You won!!')
+            break
+
+        # Now its computer's turn
+        # Computer will choose any number between 0 to 9
+
+        computer_number= randint(1,9)
+
+        # To check if user number and computer number match or not
+        ## If they match then computer must again choose a number 
+        ## If number selected by computer has 'O' or 'X' at that position then computer must select number again
+        while (computer_number==usr_number or d[computer_number]=='O' or d[computer_number]=='X' ):
+            computer_number= randint(1,9)
+
+
+        if d[computer_number] == ' ' :
+            d[computer_number] = computer_input
+
+        #clear screen here
+        clear_output()
+
+        # Print the board
+        print(line.format(d[1],d[2],d[3],d[4],d[5],d[6],d[7],d[8],d[9])+'\n')
+
+        # Condition to check if computer has won or not
+        # Check win condition on rows
+        if (d[1]==d[2]==d[3]==computer_input) or (d[4]==d[5]==d[6]==computer_input)or (d[7]==d[8]==d[9]==computer_input):
+            print('Computer won!!')
+            condition = True
+
+        # Check win condition on column
+        elif (d[1]==d[4]==d[7]==computer_input) or (d[2]==d[5]==d[8]==computer_input) or (d[3]==d[6]==d[9]==computer_input):
+            print('Computer won!!')
+            condition = True
+
+        # Check win condition on diagonals
+        elif  (d[7]==d[5]==d[3]==computer_input) or (d[1]==d[5]==d[9]==computer_input):
+            print('Computer won!!')
+            condition = True
+
+
+    usr_input = input("Enter your choice 'X' or 'O' or 'NO' to exit game: ").upper()