revised #182
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revised #182
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nanashima
requested changes
Jul 2, 2022
src/array.c
Outdated
| int main(){ | ||
| int i, lb, ub; | ||
| scanf("%d%d", &n, &k); | ||
| for(i = 0; i < n; i++){ | ||
| scanf("%d", &A[i]); | ||
| } | ||
| lb = 0; |
src/apple.c
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| int main(){ | ||
| int i, lb, ub; | ||
| scanf("%d%d", &n, &k); | ||
| for(i = 0; i < n; i++){ | ||
| for(i = 1; i <= n; i++){ |
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配列は0から始まります．
(n=100000のときこれだと配列外参照します．)
src/apple.c
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| while(ub - lb > 1) { | ||
| int mid = (lb + ub) / 2; | ||
| siguma = 0; | ||
| for(i = 1; i <=n; i++){ |
src/spear.c
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| @@ -8,10 +8,26 @@ int A[100000]; | |||
| int main(){ | |||
| int i, lb, ub; | |||
| scanf("%d%d", &n, &k); | |||
| for(i = 0; i < n; i++){ | |||
| for(i = 1; i <= n; i++){ | |||
|
修正しましたので確認お願いします。 |
nanashima
requested changes
Jul 16, 2022
src/spear.c
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| printf("%d\n", ub); |
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lb:k本の槍が作れると分かっている槍の長さ
ub:k本の槍が作れないと分かっている槍の長さ
としているならば，出力すべきはk本の槍が作れる槍の長さの最大値なのでlbです．
src/spear.c
Outdated
| @@ -11,7 +11,23 @@ int main(){ | |||
| for(i = 0; i < n; i++){ | |||
| scanf("%d", &A[i]); | |||
| } | |||
| lb = 0; | |||
| ub = 1000000000; | |||
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その場合長さ10^9の槍はまだ作れる可能性があるので，この初期値は不適切です．
(長さ10^9の木から長さ10^9の槍は作れる)
|
再修正しましたので確認お願いいたします。 |
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仕事の配分が難しかったです。