adding interview repl code from Aug 20th

InterviewWorkshops/GraphSearching.py

@@ -0,0 +1,168 @@
+#######################################
+# Problem 1: broken typewriter:
+#######################################
+# A typewriter is broken and the letter ‘e’ can’t be typed out. Instead, it will print a space. For ex:
+#   Original: “i have a dream” →
+#   Typed:    “I hav  a dr am”.
+
+# Given a string typed on this machine and a dictionary of words, return all possible original sentences it could be.
+
+# Assumptions:
+# Single Sentence
+# No Symbols
+# Case-insensitive
+# One space between words in original
+
+
+dictionary = {"i", "have", "a", "dream", "howdy", "yall", "aeon", "on", "aeaea", "aea"}
+
+test1_pre = "I hav  a dr am"
+test1_post = ["i have a dream"]
+
+test2_pre = "howdy yall"
+test2_post = ["howdy yall"]
+
+test3_pre = "a on"
+test3_post = ["a on", "aeon"]
+
+test4_pre = "fvabjwhklj g"
+test4_post = []
+
+test5_pre = "a a a a a a a a a"
+test5_post = ["aea a", "a aea", "a a a", "aeaea"]
+
+
+
+def broken_type_step(split_string, index, curr_sen):
+
+    # determines if a space is an e or a space
+    # base case
+    if index >= len(split_string):
+        return [curr_sen[1:]]
+
+    # recursive case, index < len(split_string)
+    curr_word = split_string[index]
+    new_sentences = []
+
+    # is curr_word in dictionary
+    if curr_word in dictionary:
+        new_sen = curr_sen + " " + curr_word
+        new_sentences.extend(broken_type_step(split_string, index + 1, new_sen))
+
+    # is curr_word merged with another individual word in the dictionary
+    if index + 1 < len(split_string):
+        next_word = split_string[index + 1]
+        if (curr_word + "e" + next_word) in dictionary:
+            new_sen = curr_sen + " " + curr_word + "e" + next_word
+            new_sentences.extend(broken_type_step(split_string, index + 2, new_sen))
+    return new_sentences
+
+
+def broken_type(typed):
+    # returns list of strings
+    split_string = typed.lower().split(" ")
+    return broken_type_step(split_string, 0, "")
+
+
+print(test1_pre, "\n", broken_type(test1_pre), " = ", test1_post)
+print()
+print(test2_pre, "\n", broken_type(test2_pre), " = ", test2_post)
+print()
+print(test3_pre, "\n", broken_type(test3_pre), " = ", test3_post)
+print()
+print(test4_pre, "\n", broken_type(test4_pre), " = ", test4_post)
+
+# print(test5_pre, "\n", broken_type(test5_pre), " = ", test5_post)
+
+#######################################
+
+
+
+
+
+print("\n#######################################")
+
+
+
+
+
+
+#######################################
+# Problem 2:
+#######################################
+# Given a 2D matrix of booleans, "1" means there’s “land” at that tile, and "0" means there’s “water” at that tile. Assign a height to every tile such that:
+# Water tiles are always height = 0
+# Two adjacent tiles differ by <= 1
+
+# Report the height of the highest peak you can possibly build according to these rules
+
+# Assumptions:
+# Diagonal-neighbors are not adjacent
+# Report “-1” or “Infinite” if only land
+# No constraints at edges of the matrix
+# Square Map of booleans
+
+
+test1_pre = [[0,1,1],
+              [1,1,1],
+              [1,1,1]]
+test1_post = 4
+
+test2_pre = [[1,1],
+              [1,1]]
+test2_post = -1
+
+test3_pre = [[0,0,0],
+              [0,0,0],
+              [0,0,0]]
+test3_post = 0
+
+test4_pre = [[1,1,1],
+              [1,0,1],
+              [1,1,1]]
+test4_post = 2
+
+
+def tallest_peak_step(seen, discovered, bool_map):
+  new_discovered = set()
+  for i,j in discovered:
+    if i > 0:
+      if (i-1,j) not in seen:
+        new_discovered.add((i-1,j))
+    if i+1 < len(bool_map):
+      if (i+1,j) not in seen:
+        new_discovered.add((i+1,j))
+    if j > 0:
+      if (i,j-1) not in seen:
+        new_discovered.add((i,j-1))
+    if j+1 < len(bool_map):
+      if (i,j+1) not in seen:
+        new_discovered.add((i,j+1))
+
+  return new_discovered
+
+def tallest_peak(bool_map):
+  water_tiles = set()
+  for i in range(len(bool_map)):
+    for j in range(len(bool_map)):
+      if bool_map[i][j] == 0:
+        water_tiles.add((i, j))
+
+  tallest_peak = -1
+  seen = set()
+  discovery_set = water_tiles
+  while len(discovery_set) > 0:
+    tallest_peak += 1
+    seen = seen.union(discovery_set)
+    discovery_set = tallest_peak_step(seen, discovery_set, bool_map)
+
+  return tallest_peak
+
+print()
+print([print(line) for line in test1_pre], "\n", tallest_peak(test1_pre), "=",  test1_post)
+print()
+print([print(line) for line in test2_pre], "\n", tallest_peak(test2_pre), "=",  test2_post)
+print()
+print([print(line) for line in test3_pre], "\n", tallest_peak(test3_pre), "=",  test3_post)
+print()
+print([print(line) for line in test4_pre], "\n", tallest_peak(test4_pre), "=", test4_post)