Modified power_of_n.py

power_of_n.py

@@ -1,57 +1,58 @@
-#Python program to calculate x raised to the power n (i.e., x^n)
-
-# Script Name		: power_of_n.py
-# Author		    : Himanshu Gupta
-# Created			: 2nd September 2023
-# Last Modified		:
-# Version			: 1.0
-# Modifications		:
-# Description		: Program which calculates x raised to the power of n, where x can be float number or integer and n can be positive or negative number
-# Example 1:
-
-# Input: x = 2.00000, n = 10
-# Output: 1024.00000
-# Example 2:
-
-# Input: x = 2.10000, n = 3
-# Output: 9.26100
-# Example 3:
-
-# Input: x = 2.00000, n = -2
-# Output: 0.25000
-# Explanation: 2^-2 = 1/(2^2) = 1/4 = 0.25
-
-#Class 
-class Solution:
-
-    def binaryExponentiation(self, x: float, n: int) -> float:
-        if n == 0:
-            return 1
-
-        # Handle case where, n < 0.
-        if n < 0:
-            n = -1 * n
-            x = 1.0 / x
-
-        # Perform Binary Exponentiation.
-        result = 1
-        while n != 0:
-            # If 'n' is odd we multiply result with 'x' and reduce 'n' by '1'.
-            if n % 2 == 1:
-                result *= x
-                n -= 1
-            # We square 'x' and reduce 'n' by half, x^n => (x^2)^(n/2).
-            x *= x
-            n //= 2
-        return result
-
-
-obj = Solution() #Creating object of the class Solution
-
-#Taking inouts from the user
-x = float(input("Enter the base number: "))
-n = int(input("Enter the power number: "))
-
-#calling the function using object obj to calculate the power
-answer = obj.binaryExponentiation(x, n)
-print(answer) #answer
+# Assign values to author and version.
+__author__ = "Himanshu Gupta"
+__version__ = "1.0.0"
+__date__ = "2023-09-03"
+
+def binaryExponentiation(x: float, n: int) -> float:
+    """
+    Function to calculate x raised to the power n (i.e., x^n) where x is a float number and n is an integer and it will return float value
+
+    Example 1:
+
+    Input: x = 2.00000, n = 10
+    Output: 1024.0
+    Example 2:
+
+    Input: x = 2.10000, n = 3
+    Output: 9.261000000000001
+
+    Example 3:
+
+    Input: x = 2.00000, n = -2
+    Output: 0.25
+    Explanation: 2^-2 = 1/(2^2) = 1/4 = 0.25
+    """
+
+    if n == 0:
+        return 1
+
+    # Handle case where, n < 0.
+    if n < 0:
+        n = -1 * n
+        x = 1.0 / x
+
+    # Perform Binary Exponentiation.
+    result = 1
+    while n != 0:
+        # If 'n' is odd we multiply result with 'x' and reduce 'n' by '1'.
+        if n % 2 == 1:
+            result *= x
+            n -= 1
+        # We square 'x' and reduce 'n' by half, x^n => (x^2)^(n/2).
+        x *= x
+        n //= 2
+    return result
+
+
+if __name__ == "__main__":
+    print(f"Author: {__author__}")
+    print(f"Version: {__version__}")
+    print(f"Function Documentation: {binaryExponentiation.__doc__}")
+    print(f"Date: {__date__}")
+
+    print() # Blank Line
+
+    print(binaryExponentiation(2.00000, 10))
+    print(binaryExponentiation(2.10000, 3))
+    print(binaryExponentiation(2.00000, -2))
+