all 3 problems

[avishwak]

No description provided.

[super30admin]

1. Correctness:

   • Problem 1 (Find First and Last Position): The solution correctly implements two binary searches to find the first and last occurrences of the target. It handles edge cases well, such as when the target is at the beginning or end of the array.
   • Problem 2 (Find Minimum in Rotated Sorted Array): The solution correctly identifies the minimum element by comparing the middle element with the rightmost element. However, the condition nums[mid] >= nums[low] could be simplified to just check the right half since the left half is already sorted.
   • Problem 3 (Find Peak Element): The solution correctly identifies a peak element by comparing the middle element with its neighbors. It handles edge cases like single-element arrays and boundaries well.

2. Time Complexity:

   • All three solutions correctly achieve O(log n) time complexity, which is optimal for binary search problems.

3. Space Complexity:

   • All solutions correctly use O(1) additional space, which is optimal.

4. Code Quality:

   • The code is generally well-structured and readable.
   • For Problem 1, the helper functions findFirst and findLast are well-named and modular.
   • For Problem 2, the variable name res could be more descriptive (e.g., min_val).
   • For Problem 3, the logic is clear, but the condition mid == 0 or nums[mid-1] < nums[mid] could be simplified for better readability.

5. Efficiency:

   • Problem 1: No major optimizations needed.
   • Problem 2: The condition nums[mid] >= nums[low] could be simplified since the left half is already sorted if nums[mid] > nums[high].
   • Problem 3: The logic is efficient, but the condition checks could be slightly refactored for clarity.