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Solutions for exercises No.3 #8
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val stack = LinkedList<Char>() | ||
expression.forEach { | ||
when (it) { | ||
in brackets.values -> stack.push(it) |
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This is the correct implementation. 👏🏻
One potential nitpick here is that you are creating a new list of values and keys on every item you iterate, which can be improved if we assigned brackets.values
and brackets.keys
to variables before we start iterating over the chars in the expression.
@@ -10,29 +10,49 @@ package exercise3.task4 | |||
* Find all the drivers who performed no trips. | |||
*/ | |||
internal fun TaxiPark.findFakeDrivers(): Set<Driver> { | |||
TODO("Implement me!!!") | |||
return this.allDrivers.minus(this.trips.map { it.driver } | |||
.intersect(this.allDrivers)) |
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We do not need an intersect
call here.
Its enough to subtract allDrivers - trips.map { it.drivers }
to get the result.
} | ||
|
||
/** | ||
* Subtask 2: | ||
* Find all the clients who completed at least the given number of trips. | ||
*/ | ||
internal fun TaxiPark.findFaithfulPassengers(minTrips: Int): Set<Passenger> { | ||
TODO("Implement me!!!") | ||
println(this.trips.flatMap { it.passengers } |
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nit: clean up unnecessary println
.groupingBy { it } | ||
.eachCount()) | ||
|
||
return this.trips.flatMap { it.passengers } |
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Well done! 👏🏻
TODO("Implement me!!!") | ||
return this.trips | ||
.filter { it.discount != null } | ||
.flatMap { it.passengers } |
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Your solution returns a set of passengers who had at least one trip with the discount.
The assignment request is to return a list of passengers who had more than half of the trips with the discount.
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