Added a random comment

[zchisholm]

Added a random comment for testing.

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Name	Status	Preview	Comments	Updated (UTC)
z-cord	✅ Ready (Inspect)	Visit Preview	💬 Add feedback	Nov 24, 2024 1:00am

[zenseireviews]

invite.ts

Instead of querying the database for the invite twice, you can query it once and store the result in a variable.
Create Issue

    const invite = await ctx.db.get(inviteId);
    if (!invite || invite.expiresAt && Date.now() > invite.expiresAt || invite.maxUses && invite.uses >= invite.maxUses) {
      if (!invite) {
        throw new Error("Invite not found.");
      } else if (invite.expiresAt && Date.now() > invite.expiresAt) {
        throw new Error("Invite expired");
      } else if (invite.maxUses && invite.uses >= invite.maxUses) {
        throw new Error("Invite has been used too many times");
      }
    }

Use optional chaining to simplify the code and make it more readable.
Create Issue

    const invite = await ctx.db.get(inviteId);
    if (!invite?.expiresAt || !invite?.maxUses || Date.now() > invite?.expiresAt || invite?.uses >= invite?.maxUses) {
      if (!invite) {
        throw new Error("Invite not found.");
      } else if (invite.expiresAt && Date.now() > invite.expiresAt) {
        throw new Error("Invite expired");
      } else if (invite.maxUses && invite.uses >= invite.maxUses) {
        throw new Error("Invite has been used too many times");
      }
    }